India does not have an ICBM programme

[lockh33d]

lol
He thinks, he has invented something! What is the point of putting those BS here. Now some day another will come and say I proved E=MC^2 wrong it is E=MC^22! Sigh!

No, you're wrong and I'm here to correct you. You should be appreciating my suggestion and presence here. I expect a "get lost" from you in your reply but that's OK, I've already made your correction.

 

[moody]

All your calculations weren't required cause this is what he said

"We put satellites into Geosynchronous orbit which is 36000 km away"

He was talking about the altitude from mean sea level and not from the center of the Earth. And in Aerospace, we do not talk about geosynchronous orbit at 42k kms from earth's center but at 36k km from the sea level, because when we talk in terms of thrust required, we do not calculate the first 6.4 k kms ie the radius of the earth, because that would require a lot more thrust to escape the gravity, whereas in reality we don't require that much thrust. We just need o calculate the thrust required to push the satellite from 6.4k kms to 42k kms from the earth's center.

If we take your calculations, the satellite would keep moving away from earth at a very rapid pace and in a few hours escape the gravity and in no time will be lost in space.

If you're still in doubt I can do the calculations for you.

Derivation of geostationary altitude​

Geostationary orbit - Wikipedia, the free encyclopedia

 

[lockh33d]

35,700 KM should be the the distance of the center of gravity of the spacecraft and the centre point of the earth in order to achieve an Ideal GSO.

No way, are you serious, go back to my calculation. I PROVED it to you, with the period of the earth taken into account, 42 x 10^3 KM is the distance between the 2 point sources.

 

[lockh33d]

Derivation of geostationary altitude​

Geostationary orbit - Wikipedia, the free encyclopedia

READ:

"Geostationary orbits can be achieved only very close to the ring 35,786 km (22,236 mi) high, directly above the equator."

IN THE INTRO, FIRST LINE IN FACT.

And you were saying?

 

[jagjitnatt]

No way, are you serious, go back to my calculation. I PROVED it to you, with the period of the earth taken into account, 42 x 10^3 KM is the distance between the 2 point sources.

and 36k kms between surface of earth and the GSO

 

[jagjitnatt]

Everyone is saying the same thing.

GSO is 36k kms from surface but 42k kms from centre of earth. What is so confusing?

 

[lockh33d]

and 36k kms between surface of earth and the GSO

Yes, I never doubted that. But universally, no one uses the altitude above the earth's surface for reference. We want the "point," where gravitational force=infinite, or "0"

So at surface level, it is around 6x10^3 KM above infinite, hence it cannot be taken as the point. We need to take into account of the earth's center.

Hence the confusing thing was that this all started with 36k's being GSO. Which I took in to be 36K's above point source.

 

[Kinetic]

Whats going on??!!! Troll!!!!

8th grade student in defence.pk!
Geosynchronous orbit is 42000 km away!
The Moon is 42000000000000 km away!
The Sun is 42000000000000000000000000000000000000 km away!

Come back to the topic!

 

[moody]

Everyone is saying the same thing.

GSO is 36k kms from surface but 42k kms from centre of earth. What is so confusing?

The highlighted part is incorrect.

You are equating GSO and GTO.

GSO is a perfect circular orbit while GTO is a highly elliptical orbit.

 

[jagjitnatt]

Whats going on??!!! Troll!!!!

8th grade student in defence.pk!
Geosynchronous orbit is 42000 km away!
The Moon is 42000000000000 km away!
The Sun is 42000000000000000000000000000000000000 km away!

Come back to the topic!

Actually he is right in his own way. We usually take the mass from the centre of the object where gravitational force is concentrated at the point.

He is using simple equations to prove it.

I instead use equations derived specially for the purpose of launching a satellite. Because the radius, gravitational pull etc are always constant we don't take the center of earth every time. But for general physics we always use center of gravitation.

 

[lockh33d]

The highlighted part is incorrect.

You are equating GSO and GTO.

GSO is a perfect circular orbit while GTO is a highly elliptical orbit.

Nope, I'm going to re-direct you to wiki:

Geosynchronous orbit - Wikipedia, the free encyclopedia

"All Earth geosynchronous orbits have a semi-major axis of 42,164 km (26,199 mi)"

From this, it is a circular orbit, with multiple planes, but with the center of rotation about the earth's center. Hence, GEO=GSO in terms of distance from the 2 objects in space.

 

[lockh33d]

Actually he is right in his own way. We usually take the mass from the centre of the object where gravitational force is concentrated at the point.

He is using simple equations to prove it.

I instead use equations derived specially for the purpose of launching a satellite. Because the radius, gravitational pull etc are always constant we don't take the center of earth every time. But for general physics we always use center of gravitation.

Thank you for understanding.

 

[Kinetic]

Actually he is right in his own way. We usually take the mass from the centre of the object where gravitational force is concentrated at the point.

He is using simple equations to prove it.

I instead use equations derived specially for the purpose of launching a satellite. Because the radius, gravitational pull etc are always constant we don't take the center of earth every time. But for general physics we always use center of gravitation.

I am not going into details but answer me one question what it has to with with this....

"We put satellites into Geosynchronous orbit which is 36000 km away"

Isn't he just trolling in this thread?

 

[lockh33d]

I am not going into details but answer me one question what it has to with with this....

"We put satellites into Geosynchronous orbit which is 36000 km away"

Isn't he is just trolling in this thread?

No your statement is very confusing to the public. It's better to make things clear before progressing.

For the record, there are Indians in the Chinese threads posting flame comments with the Chinese not commenting "Troll troll troll" to every flame post made. Why are you over reacting so much?

 

[jagjitnatt]

The highlighted part is incorrect.

You are equating GSO and GTO.

GSO is a perfect circular orbit while GTO is a highly elliptical orbit.

What you say is correct, but the altitude of GSO from earth's surface is 35786 km.

GTO is an intermediate orbit which is reached for the satellite to be put in the GSO.