India does not have an ICBM programme

[lhuang]

Actually it doesn't matter which term he uses, my calc proves true for both cases, considering the fact that the plane of orbit incorporates the center of earth as the center of orbit. He just needs to know that in physics, that point-point distance is the one we talk about, not surface-point.

No, geo-stationary and geo-synchronous are analogous hence it does matter which term is used.

 

[lockh33d]

I think he was talking about geo-stationary orbit. It's a commonly confused term.

PS: I am new to this website.

There was no need to do the maths, it is common knowledge that geo synchronous orbit is ~42k km.

Btw, both geosynchronous and geostationary orbits have ~42K's. Just that geostationary orbits are restricted to just one plane of orbit.

Lastly, WELCOME TO THE FORUMS, don't let the Indians scare you off! I'm serious! lol

 

[lockh33d]

No, geo-stationary and geo-synchronous are analogous hence it does matter which term is used.

Exactly what I said before you .

 

[lhuang]

Geo synchronous orbit(GSO) is 35,700 KM exact.

While Geo stationary transfer orbit (GTO) is an elliptical path with apogee at 36000 km and Perigee of few hundred kilometers.

See even I got confused.

 

[moody]

No, geo-stationary and geo-synchronous are analogous hence it does matter which term is used.

Geo synchonous and geo stationary are one and the same but GSO and GTO are different terms. GTO is a pre GSO phase and a spacecraft has to go under complex manouvers to reach GSO from GTO.

 

[Kinetic]

Yes, you can fool the majority but you can't fool me.

lol Than what you are? You don't know more than 8th grade physics.

Lastly, if you can't understand 7th/8th grade physics, what can you understand ?

Who brings 8th grade physics into space discussion!!! Why do you think everyone is like you that dont know more than 8th grade physics?

It has everything to the topic, because ICBM's have the power to be used as delivery systems to out space, and place goods in geosynchronous orbit.

You understood 0 out of ten! Waste!

 

[lockh33d]

Geo synchronous orbit(GSO) is 35,700 KM exact.

While Geo stationary transfer orbit (GTO) is an elliptical path with apogee at 36000 km and Perigee of few hundred kilometers.

You didn't read what I said. Distances are given by point sources, that is from the center of the earth. That's how calc are done. That's what people state because it makes life so much easier. We don't use surface of earth to whatever.

 

[moody]

Btw, both geosynchronous and geostationary orbits have ~42K's. Just that geostationary orbits are restricted to just one plane of orbit.

This is misleading and incorrect.

 

[lockh33d]

lol Than what you are? You don't know more than 8th grade physics.


Who brings 8th grade physics into space discussion!!! Why do you think everyone is like you that dont know more than 8th grade physics?



You understood 0 out of ten! Waste!

I only put 8th grade material here, and nothing suggests I haven't a clue anything above that. However for you my friend...You're clueless on this matter, perhaps start from scratch with physics? Or go try and get an A for literature? I suggest William Shakespeare if offered in India Or else the readings of Mohat Mohat Ghandi would suffice.

 

[lhuang]

Btw, both geosynchronous and geostationary orbits have ~42K's. Just that geostationary orbits are restricted to just one plane of orbit.

Lastly, WELCOME TO THE FORUMS, don't let the Indians scare you off! I'm serious! lol

Sorry, just no, Google it if you have to.

 

[moody]

You didn't read what I said. Distances are given by point sources, that is from the center of the earth. That's how calc are done. That's what people state because it makes life so much easier. We don't use surface of earth to whatever.

35,700 KM should be the the distance of the center of gravity of the spacecraft and the surface of the earth in order to achieve an Ideal GSO.

 

[jagjitnatt]

Actually it doesn't matter which term he uses, my calc proves true for both cases, considering the fact that the plane of orbit incorporates the center of earth as the center of orbit. He just needs to know that in physics, that point-point distance is the one we talk about, not surface-point.

All your calculations weren't required cause this is what he said

"We put satellites into Geosynchronous orbit which is 36000 km away"

He was talking about the altitude from mean sea level and not from the center of the Earth. And in Aerospace, we do not talk about geosynchronous orbit at 42k kms from earth's center but at 36k km from the sea level, because when we talk in terms of thrust required, we do not calculate the first 6.4 k kms ie the radius of the earth, because that would require a lot more thrust to escape the gravity, whereas in reality we don't require that much thrust. We just need o calculate the thrust required to push the satellite from 6.4k kms to 42k kms from the earth's center.

If we take your calculations, the satellite would keep moving away from earth at a very rapid pace and in a few hours escape the gravity and in no time will be lost in space.

If you're still in doubt I can do the calculations for you.

 

[lockh33d]

This is misleading and incorrect.

Geosynchronous orbits have periods the same as a planet's rotation. Geostationary orbits have periods the same as a planet's rotation BUT ONLY ACROSS THE EQUATORIAL PLANE.

Since the periods are the same, angular velocity will be the same. Hence, with my calculation, all other variables are CONSTANTS, giving you the SAME END RESULT VALUE.

 

[Kinetic]

This is misleading and incorrect.

lol
He thinks, he has invented something! What is the point of putting those BS here. Now some day another will come and say I proved E=MC^2 wrong it is E=MC^22! Sigh!

All your calculations weren't required cause this is what he said

"We put satellites into Geosynchronous orbit which is 36000 km away"

He was talking about the altitude from mean sea level and not from the center of the Earth. And in Aerospace, we do not talk about geosynchronous orbit at 42k kms from earth's center but at 36k km from the sea level, because when we talk in terms of thrust required, we do not calculate the first 6.4 k kms ie the radius of the earth, because that would require a lot more thrust to escape the gravity, whereas in reality we don't require that much thrust. We just need o calculate the thrust required to push the satellite from 6.4k kms to 42k kms from the earth's center.

If we take your calculations, the satellite would keep moving away from earth at a very rapid pace and in a few hours escape the gravity and in no time will be lost in space.

If you're still in doubt I can do the calculations for you.

Wasting your time. He cant control himself to post what he has learned in his book! And we are talking about ICBM and GSLV!

 

[lockh33d]

All your calculations weren't required cause this is what he said

"We put satellites into Geosynchronous orbit which is 36000 km away"

He was talking about the altitude from mean sea level and not from the center of the Earth. And in Aerospace, we do not talk about geosynchronous orbit at 42k kms from earth's center but at 36k km from the sea level, because when we talk in terms of thrust required, we do not calculate the first 6.4 k kms ie the radius of the earth, because that would require a lot more thrust to escape the gravity, whereas in reality we don't require that much thrust. We just need o calculate the thrust required to push the satellite from 6.4k kms to 42k kms from the earth's center.

If we take your calculations, the satellite would keep moving away from earth at a very rapid pace and in a few hours escape the gravity and in no time will be lost in space.

If you're still in doubt I can do the calculations for you.

Then I feel sorry for you. In "Aerospace," you need to find the potential energy with which you have at the starting altitude.

⌀=GM/r

r=distance BETWEEN 2 POINT SOURCES. POINT. That is the center of the earth and the center of the spacecraft, which can be neglected because of the tiny discrepancies from the edge and the center of the spacecraft.