...
If there is a god of radar physics, he must be laughing his guts out when he read the nonsense about bi-static radar operation from you. Anyway...What the hell does this...'
inhomogeity of the medium'...mean? The 'medium' here is air, or rather relatively 'empty space'. A bi-static configuration exploits the greater forward scatter signals. So by your argument here...
the inhomogeity of the medium...whatever the hell that mean...make a bi-static configuration inefficient, then that would make the mono-static configuration completely worthless. And yet mono-static radars are prevalent. As I have pointed out before and will repeat, in theory, a bi-static configuration is low observable aircrafts' best detector precisely because of those forward scatter signals. So in trying to prove me wrong about canards, you just ended up calling bi-static radars worthless against 'stealth'. Am beginning to suspect that these are not your words but someone else's that you are trying to pass off as your own. There seems to be no technical consistency.
That is why bi-static radars are no panacea to 'stealth' despite what some chinese fanboys would like believe whenever they tried to downplay the F-22. This is not because bi-static sensor systems, like the Kolchuga or Silent Sentry, do not work but because a bi-static configuration is inherently structurally intensive, requiring physically distinct transmitter and receiver stations.
Meaningless drivel. The point I am making is that diffraction energy in a contributor to a body's total RCS. So far you have yet to show the readers a source that says otherwise.
Sandwich? When a fighter launches a semi-active radar guided missile, we have an airborne bi-static configuration.
The parent aircraft illuminated the target, the missile is the receiver and its position is an offset from the parent's position, thereby creating a 'bi-static triangle'...
Bistatic radar noncooperative illumination synchronization techniques
When we have data link capability, the transmitter aircraft is one leg of that triangle, the target is another leg, and the receiver aircraft is the final leg. It does not matter if there is one or ten receiver aircrafts, for each receiver there is only one bi-static triangle. That mean we can have ten bi-static triangles from one transmitter. The receivers do not have to be directly opposite of the transmitter. Forward scatter does not mean literally straight forward but can be angular as the signal is deflected off the target. If anything, the ideal bi-static position is when the transmitter-target-receiver triangle is like below...
...But since airborne targets are in motion we know this is not possible. A bi-static configuration can exploit diffraction or deflection or both. So once again your ignorance and pretense is exposed.
More like made up 'facts' and 'truths'. But hey...Since when is a communist an honest person?
The JXX is supposedly equipped with canards. Naturally the question would be if canards are detrimental to its RCS reduction. I presented arguments and sources that say leading and trailing edges produces diffraction fields that are detrimental to RCS reduction.
RCS Pylons | Antenna Measurement Solutions
As I always find: too many people are just too much letting themselves entangled with trivial details but forget the essences of principles. Those people include federal employees, defense expertise, national lab leaders, and even some university professors... Frankly, I’m fed up with those fools. And I don’t understand why you make such a simple thing so complex, provided that you want to fool the credulous.
a) any inhomogeneity of the media will cause EM wave to going in a bent way (roughly speaking).
Canards do introduce the inhomogeneity in general.
If you have any language problems because of your upbringings, from EM point of view, just let you know that dialectic property can be described with permittivity and permeability of the medium, including vacuum. In general they are the function of space (x,y,z) and EM frequencies. If they are constants in terms of space (x,y,z), they are spatially homogenous. If EM wave travels within such a homogenous medium, no scattering, and thus, loosely speaking, no diffraction/reflection will happen.
Why I say it loosely speaking? Because any other phenomena (reflection, diffraction, etc.) are part of scattering. Reflection is specular scattering, diffraction is interference among (in general) forward scattering waves. Diffusion is non-specular scattering. Strictly speaking, when waves move to next position in a medium, it is a result of diffraction (or interference) of all waves from their previous position(s). Thus, we can say all earlier waves are “primary sources” of next waves, and next waves are “secondary sources” to yet the third waves. This is how the “snapshots” are when we strictly and correctly visualized the EM propagation.
If you have a sense of quantum mechanics, those perturbations (inhomogeneity ) to the medium function like potential wells that cause waves to scatter (reflection/scattering/diffraction, what ever you name it.)
b) In general, direct reflection (specular part) contains the majority of the energy, unless the surface/interface where the wave encountered is very rough. Rough or not is compared with the wavelength. If the size of “humps” or “dents” are comparable with the EM wavelength it is rough. Thus for longer wavelength, a surface usually looks more smooth.
Physically, it is very easy to understand, as specular part of the energy comes as zero-th order approximation from
Born Approximation. Any diffuse scattering are in higher order.
This is perhaps why the first order correction for stealth, in general, should be geometrical to deflect the specular part of the energy. Even it will introduce aerodynamic instability, the cost is still comparatively low.
If specular energy is absent due to absorption or deflection or strong diffusion, people may then consider higher order approximations.
Even according you, diffractive energy goes off the front canards and happens(!) to be caught by the wings, yes it serves as a signal, but still 1) in general diffracted energy is weak compared with specular energy, 2) second reflection will make it even weaker. 3) the weak signal may well be intermittent or fortuitous due to the precise match of the paths. Above talk is in absence of specular part.
c) RAM still may/may not substantially diminishes diffraction, depending on the physical nature/structure of the material and the shining wavelength. Moreover, if only leading edges are RAM coated, it helps but perhaps still not enough as multiple scattering may hit somewhere other than the leading edge!
“An airfoil is conducive to surface traveling waves, which do not lose energy as it traverse the wing's surface.”
Man, you are so reckless! Hahahaha, the mere “conductive” can sustain a traveling wave to stay forever. Gee, you are the person to get
fa(ke)sics Nobel Prize soon, as you are in open defiant of energy conservation!
Just for your EM abc, check out formula (8.12) in Chapter 8 of J.D. Jackson’s <Classical Electrodynamics>, 2nd Edition, published by John Wiley & Sons 1975:
Energy of surface wave dissipated in a unit area da in a conductor is dP(loss)/da = [1/(4pi)](nu_e*omega*delta/4)(H_parallel)^2, where delta is inversely proportional to sqrt(conductivity) (formula 8.8 of the same chapter)
Unless your airplane has wings of superconductor,
the delta will never be zero as the conductivity is always finite and the wave energy will ALWAYS diminish in the skin of surface.
For non-conductive composite materials, this phenomenon normally may not even exist.
The product guide state...
Nowhere have I asserted with absolute certainty that canards are detrimental to RCS reduction, only that conventional technical wisdom from decades of laboratory and field experience showed that edge diffraction fields are detrimental to RCS reduction if the aircraft design does not take them into consideration. There is no shortage of those literature...
Marietta Scientific, Inc. - RCS Reduction Short Course
Got that? There are different types of traveling waves and that a leading edge does produce a diffraction field.
But here you are trying in vain to dismiss decades worth of technical experience and literature in trying to support the JXX. You are a fanboy of lies and deceit.
No wonder you have so many foolish statement with respect to EM theory, because you are a student of Marietta Scientific, Inc. Hahahaha…. But if those people want to talk serious academics, I’ll kick their @ss out of my office door.
Those are the parasites of interest groups that suck our taxpayers’ money into their pocket and hoax your credulous boys into nowhere.
I’m telling you that those physics ignorant Indians thanked you not because you were right in physics, but rather because you are anti-China, as they usually foolishly demonstrate themselves. And
you physics are deadly wrong in lots of places, including, but not limited to your previous statements about Bernoulli equation. As a typical low-key Chinese descendant, I normally refuse to be dragged into an academic debase with pseudo-professional and false-expert. Does anyone try to discuss physics with a more ideological fundamentalist than a physicist?
Tell us how can one convert Pope into Judaism?
If your type of fundamentalists are in lead of this country (USA), second “Christmas go home” farce will certainly and unfortunately advent in near future, and more innocent people will suffer...
BTW, when can we marlvel you sandwiching an enemy plane of superconductor with your bi-statis radar planes to form a triangle?