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Question on the Radar?

zon95

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Conventional aircraft return much larger signatures. ECM is limited by the power of the airborne jammer. Therefore, a smaller aircraft RCS is easier to cloak because it requires less power from the jammer. An aircraft that reduces its front-aspect signature by a factor of 10 cuts the notional detection range by 44 percent. The power required in the ECM jammer also decreases in proportion. For the same amount of power, ECM can jam more effectively.

The Radar Game

This site refers to the detection range of the radar?this is correct?and a civilian who can calculate the detection range of the radar to the enemy aircraft through this way?

An aircraft that reduces its front-aspect signature by a factor of 10 cuts the notional detection range by 44 percent

Did this question, temporary I understand that RCS reduced by 10 times the radar range is reduced by 44% ?! (This means that the remaining 56%)

My example:

Radar Zaslon-M with detection range of 400 km with a target of RCS = 20 m2, so the F-15 with RCS = 10m2 (Of course this is only the estimated parameters, greater than 2 cuts the 20 m2)
F-15 will be detected at a distance: 400 * 0.56 = 224 km


It is correct?I found that high technology cannot be calculated in such a simple formula
 
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Conventional aircraft return much larger signatures. ECM is limited by the power of the airborne jammer. Therefore, a smaller aircraft RCS is easier to cloak because it requires less power from the jammer. An aircraft that reduces its front-aspect signature by a factor of 10 cuts the notional detection range by 44 percent. The power required in the ECM jammer also decreases in proportion. For the same amount of power, ECM can jam more effectively.

The Radar Game

This site refers to the detection range of the radar?this is correct?and a civilian who can calculate the detection range of the radar to the enemy aircraft through this way?



Did this question, temporary I understand that RCS reduced by 10 times the radar range is reduced by 44% ?! (This means that the remaining 56%)

My example:

Radar Zaslon-M with detection range of 400 km with a target of RCS = 20 m2, so the F-15 with RCS = 10m2 (Of course this is only the estimated parameters, greater than 2 cuts the 20 m2)
F-15 will be detected at a distance: 400 * 0.56 = 224 km


It is correct?I found that high technology cannot be calculated in such a simple formula
Yes, it is correct. The technology is not that high. The foundation of radar detection was discovered in the late 19th century when Heinrich Hertz found that radio waves actually bounced off bodies, any kind of bodies, from buildings to trees and even off humans. It was not until WW II that we managed to use that 'bounced off' signals to create 'radar detection'.

In radar detection, NOTHING is invisible. Or that radar 'sees' everything. The question is distance and that gave us 'effective detection range'. What this mean is that if a radar signal can travel 100 km, the best range to have usable reflected signals is about 80-90 km. The atmosphere is not clean. It is very 'dirty'. Along that 100 km, there are many bodies such as birds, clouds, or rain to reduce the signal's energy. The word is 'attenuation' or losses through travel.

This attenuation or loss works both ways. The reflected signals that came from the target also loses energy on the travel back to the radar. So look at it this way, the radar signal loses energy on the way to the target, it loses some more energy when it hit the target, then it loses some more energy on the way back to the radar. This loss is called the 'inverse square law'. Look it up.

So if a target is shaped in such a way that it reflects very little of any energy that hit it, then the effective radar detection range is reduced even further because of that low energy level. Remember, radar 'sees' everything, but only by how much energy is available to it. The less energy, the shorter that distance.
 
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Did this question, temporary I understand that RCS reduced by 10 times the radar range is reduced by 44% ?!
Formula is simple: if RCS is reduced by X then detection distance will reduce by
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(fourth root of X).

So if RCS is reduced 10 times then detection range will decrease 1.78 times (fourth root of 10).

My example:

Radar Zaslon-M with detection range of 400 km with a target of RCS = 20 m2, so the F-15 with RCS = 10m2 (Of course this is only the estimated parameters, greater than 2 cuts the 20 m2)
F-15 will be detected at a distance: 400 * 0.56 = 224 km
F-15 will be detected at 336 km. (400/(fourth root of 2))
 
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