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can you solve this? not that difficult.

Ahmad

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Using minus, multiplication, addition and division solve these simple equasions:

example:

2 2 2 = 6 -------> 2+2+2=6


Here they are:

1 1 1 =6
3 3 3 =6
4 4 4 =6
5 5 5 =6
6 6 6 =6
7 7 7 =6
8 8 8 =6
9 9 9 =6
 
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3x3-3 = 6
5/5+5 = 6
(6/6)*6 = 6
7-7/7=6
8-8^0-8^0
(9 - Sqr(9)) x 9^0

Left two out :D
 
. .
3x3-3 = 6
5/5+5 = 6
(6/6)*6 = 6
7-7/7=6
8-8^0-8^0
(9 - Sqr(9)) x 9^0

Left two out :D

yes, i think 1 and 4 is to be solved. but they are easy.

how did you solve 9? can you illustrate it a bit please, because i am confused with the last symbol.
 
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I did it but using some other signs. Here is the answer.

!(1+1+1) = 6
2+2+2 = 6
(3*3)-3 = 6
!(4-(4/4)) = 6
5+(5/5) = 6
(6*6)/6 = 6
7-(7/7) = 6
8-(sqrt (sqrt(8+8))) = 6
(sqrt9 * sqrt9) - sqrt9 = 6
 
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(1+1+1)! = 6

3*3-3 = 6

(4+4) - sqrt(4) = 6

5 + (5/5) = 6

6+6-6 = 6

7- 7/7 = 6

CubeRoot(8)+CubeRoot(8)+CubeRoot(8) = 6

sqrt(9)*sqrt(9) - sqrt(9)= 6
 
Last edited:
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yes, it is complete now. i am sure there are more than one way to solve each of them.
 
. . . . . .
but you are not supposed to use zero here. all we should use is
-,+,* and /

Thats why I grew up writing computer code for problems like these :D

sum = 9 + 9 - 9
length = stringlenth(999)
sum = sum - length

return sum
 
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